2.Motion in Straight Line
easy

પ્રારંભિક સ્થિર અવસ્થામાંથી કણ $\frac{4}{3}\;ms^{-2}$ ના પ્રવેગથી ગતિ કરે છે. કણે ત્રીજી સેકન્ડમાં કાપેલું અંતર કેટલું હશે?

A

$\frac{{10}}{3}\,m$

B

$\;\frac{{19}}{3}\,m$

C

$6\,m$

D

$4\,m$

(AIPMT-2008)

Solution

$\begin{array}{l}
{\rm{Distance}}\,travelled\,in\,the\,{3^{rd}}\,{\rm{second}}\\
 = {\rm{Distance}}\,travelled\,in\,3\,s\\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, – \,d{\rm{istance}}\,{\rm{travelled}}\,{\rm{in}}\,\,{\rm{2}}\,\,{\rm{s}}{\rm{.}}\\
As,\,u = 0,\\
{S_{\left( {{3^{rd}}s} \right)}} = \frac{1}{2}a{.3^2} – \frac{1}{2}a \cdot {2^2} = \frac{1}{2}a \cdot 5\\
Give\,a\frac{4}{5}m{s^{ – 2}};\,\,\,\therefore \,\,\,{S_{\left( {{3^{rd}}s} \right)}} = \frac{1}{2} \times \frac{4}{3} \times 5 = \frac{{10}}{3}\,m
\end{array}$

Standard 11
Physics

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